Thread: Which is the best wind meter for wind estimation

I think I can feel my brain melting out my ears
thank god someone invented ballistic calculators

Distance -
angle-
Wind speed -
Wind direction -
BC-
weight-
velosity-

Bang.

Hit. Well done

For wind estimations I work off;
How much baked beans were eaten, as it is directly proportional to the amount of wind produced.

If you want to shoot straight don't eat too many and there won't be to much wind

all I really need is the wind speed meter now, hence the question.

Im keen to hear what the 30$ option is, and where to buy a kestral at a good price.
sitting on the top of a hill last night thinking I have no idea what to add in as a correction defintly gives me a push to get one

Here it is has gone up to $39 Anemometer Beaufort Scale Digital Wind Speed Meter | Trade Me I tested it by holding out the window while driving at 50kph, it gave the right speed. Good enough for me.

Found another one only $23 closes in 3 hours Digital Wind Speed Gauge / Wind Sport Anemometer | Trade Me

how good is it for input and accuraccy with putting bullets on target stug?
Im guessing low speed wind would be the hardest for a little meter to read

Seems OK, gives similar wind readings to my mates Kestrel 3500. I have made some tricky shots in the wind with it. The last one was the spiker I shot at 634yds ( I posted the video of that shot on here http://www.nzhuntingandshooting.co.n...er-video-3923/). Most of your ability to hit in the wind is what you do with the wind reading, not what it actually is. Inside 600 yds being a few mph out won't make much difference.
The best shot have made in the wind (with this wind meter) I had to allow for a strong head wind from 2 o'clock, but also had to allow for the lift generated by the wind as it blew up the slope towards me. From memory it was a 450ish yd shot on a pig, hit it exactly where I was aiming.

Thanks Stu, purchased one last night for $24 - Long range deal of the year! ;-)

Will put it through the same testing procedure that you did ;-)

An exercise in simplicity I'm sure but would it be true to say.....

that one inch of drift approximating 1 MOA at 100m with continue to be 1 MOA = 10" approx drift at 1000m with no further wind

And no wind 0-900 but 1 inch of drift 900-1000 will result in 1 inch total dirt = 0.1 MOA....

Same amount of wind at different ranges...?

I assume this is why we average the wind for the total distance calc?

There seems assumption that if the wind has blown the bullet off 1 inch at 100yd it will be 10 inch off at 1000yd without any more interaction from wind after the 100yd. To me this doesn't seem right because that would mean that the bullet would have had its direction of travel changed, I think that it would more likely be blown onto an almost parallel course one inch off its original path, not perfectly parallel but certainly close.

Thoughts?

Do you think it will move back to its original path when the wind stops blowing?

Originally Posted by Sidney

Do you think it will move back to its original path when the wind stops blowing?

Not its original path but a path with close on the same bearing/direction.

Originally Posted by Savage1

There seems assumption that if the wind has blown the bullet off 1 inch at 100yd it will be 10 inch off at 1000yd without any more interaction from wind after the 100yd. To me this doesn't seem right because that would mean that the bullet would have had its direction of travel changed, I think that it would more likely be blown onto an almost parallel course one inch off its original path, not perfectly parallel but certainly close.

Thoughts?

Thought about it for ten minutes and have come up with "Nup". My rationale behind the "Nup" conclusion is that there would need to be two changes in direction for that to occur. The first wind influence to put it off course and then some other force/influence to put it back on course. So Nup it is.

naa, not getting involved in this

Pretty sure a deviation from the altered path will (unless another force acts on it), mean that the projectile will continue on the new path. It would require another force to straighten the path to parallel with the original path..

So I believe you to be right Rushy